523=0.04x^2-8x+700

Solution for 523=0.04x^2-8x+700 equation:

523=0.04x^2-8x+700

We move all terms to the left:

523-(0.04x^2-8x+700)=0

We get rid of parentheses

-0.04x^2+8x-700+523=0

We add all the numbers together, and all the variables

-0.04x^2+8x-177=0

a = -0.04; b = 8; c = -177;
Δ = b2-4ac
Δ = 82-4·(-0.04)·(-177)
Δ = 35.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{35.68}}{2*-0.04}=\frac{-8-\sqrt{35.68}}{-0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{35.68}}{2*-0.04}=\frac{-8+\sqrt{35.68}}{-0.08}
$